Nathan Bahn Beers Law Study Lab Introduction: In this lab, we utilize a spectrometer to observe the transmittance of swingy at a certain wave length. We experimented to see if the breakwaterarity of a firmness of purpose changes the transmittance of weakly and the absorbance of that light by the solution. By observing the percent transmittance and the come up of light absorbed, we fag calculate the sum of money of color absorbing components in the solution. by this process is how we are able to discover the amount of atomic number 29 in the solution. Experimental functioning: 250 mL of the copper solution was made by creating carbon mL of the solution, reacting CuO with HNO3, and then diluting to the determine of 250 mL. Using this stock solution, variant concentrations were made and placed in the sprectrometer for observation. The absorbances and transmittances were recorded for use when identifying the amount of the color-absorbing copper ions later. A graph w as plotted of Absorbance v. bulwarkar(a) Concentration slowly see the results of the experiment. Pre-Lab Questions: 1. Absorbance = - Log10T = 2-Log10 (%T) a) 2 Log (89.95) = .0460f) 2 Log (28.18) = .5501 b) 2 Log (80.91) = .0920g) 2 Log (20.51) = .6880 c) 2 Log (59.02) = .2290h) 2 Log (17.38) = .7600 d) 2 Log (47.75) = .3210i) 2 Log (14.45) = .8401 e) 2 Log (34.83) = .

4580 2. Molar Concentration 1.213 g Cu (1 mol Cu/ 63.546 g Cu) (1 mol [Cu (H2O6)2+]/ 1 mol Cu) (1/ .100 L) = .191 M [Cu (H2O6)2+] a) M2 = (M1V1)/V2M2 = (.191 M [Cu (H2O6)2+])( 1.0 mL)/ (50.0 mL) = .0038 M b) (.191 M [Cu (H2O6)2+]) (2. 0 mL)/ (50.0 mL) = .0076 M c) (.191 M [Cu (! H2O6)2+]) (5.0 mL)/ (50.0 mL) = .0191 M d) (.191 M [Cu (H2O6)2+]) (7.0 mL)/ (50.0 mL) = .0267 M e) (.191 M [Cu (H2O6)2+]) (10.0 mL)/ (50.0 mL) = .0382 M f) (.191 M [Cu (H2O6)2+]) (12.0 mL)/ (50.0 mL) = .0458 M g) (.191 M [Cu (H2O6)2+]) (15.0 mL)/ (50.0 mL) = .0573 M h) (.191 M [Cu (H2O6)2+]) (17.0 mL)/ (50.0 mL) = .0649 M i) (.191 M [Cu...If you expect to get a full essay, order it on our website:
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